25x^2-50x=-16

Solution for 25x^2-50x=-16 equation:

25x^2-50x=-16

We move all terms to the left:

25x^2-50x-(-16)=0

We add all the numbers together, and all the variables

25x^2-50x+16=0

a = 25; b = -50; c = +16;
Δ = b2-4ac
Δ = -502-4·25·16
Δ = 900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{900}=30$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-50)-30}{2*25}=\frac{20}{50}
=2/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-50)+30}{2*25}=\frac{80}{50}
=1+3/5
$